Musical isomorphism
From Wikipedia, the free encyclopedia
In mathematics, the musical isomorphism (or canonical isomorphism) is an isomorphism between the tangent bundle TM and the cotangent bundle T * M of a Riemannian manifold given by its metric. There are similar isomorphisms on symplectic manifolds.
It is also known as raising and lowering indices.
Contents |
[edit] Introduction
A metric g on a Riemannian manifold M is a tensor field
which is symmetric and positive-definite: thus g is a positive definite smooth section of the vector bundle
of symmetric bilinear forms on the tangent bundle. At any point x∈M,
defines a linear isomorphism of vector spaces
(from the tangent space to the cotangent space) given by
for any tangent vector Xx in TxM, i.e.,
The collection of these linear isomorphisms define a bundle isomorphism
which is therefore, in particular, a diffeomorphism and is linear on each tangent space.
is called the musical isomorphism flat (
), and its inverse
is called sharp (
): sharp raises indices, flat lowers them (Gallot, Hullin & Lafontaine 2004, p. 75).
[edit] Motivation of the name
The isomorphism
(i.e.
) and its inverse
(i.e.
) are called musical isomorphisms because they move up and down the indexes of the vectors. For instance, a vector of TM is written as
and a covector as αidxi, so the index i is moved down and up in α just as the symbols flat (
) and sharp (
) move down and up the pitch of a semitone (Gallot, Hullin & Lafontaine 2004, p. 75).
[edit] Gradient, divergence and curl
The musical isomorphisms can be used to define the gradient, divergence and curl of smooth functions on
as follows:
where
is the Hodge star operator (Marsden & Raţiu 1999, p. 135). The first equation is also valid in a more general context of smooth functions on Riemannian manifolds. On symplectic manifold, the first equation defines a Hamiltonian vector field with the Hamiltonian f.
Moreover, it may be nice to notice that even the cross product can be defined using the Hodge star operator and the musical isomorphism. In fact, being v and w vector fields over
, it's easy to prove that:
[edit] References
- Gallot, Sylvestre; Hullin, Dominique; Lafontaine, Jacques (2004), Riemannian Geometry (3rd ed.), Berlin, New York: Springer-Verlag, ISBN 978-3-540-20493-0.
- Marsden, Jerrold E.; Raţiu, Tudor S. (1999), Introduction to Mechanics and Symmetry (2nd ed.), Berlin, New York: Springer-Verlag, ISBN 978-0-387-98643-2.





![\begin{align}
\nabla f &= \left( {\mathbf d} f \right)^\sharp &=\hat{g}^{-1} \circ df\\
\nabla \cdot F &= \star {\mathbf d} \left( \star F^\flat \right) \\
\nabla \times F &= \left[ \star \left( {\mathbf d} F^\flat \right) \right]^\sharp
\end{align}](http://upload.wikimedia.org/math/f/2/8/f28bcf31ca3cba0858d113ec059f8a40.png)
![\mathbf{v}\times\mathbf{w} = \left[ \star \left( \mathbf{v}^\flat \wedge \mathbf{w}^\flat \right) \right]^\sharp](http://upload.wikimedia.org/math/1/1/e/11eee4f002bc7d9933c544c0955b657f.png)

